[DML] Fan Speed Overload - Technical Correction

[doctorDHD@xxxxxxx]

Sometimes I read something that comes to the right conclusion but is just  is 
not correct technically and this is one of those times, so in the interest of 
 correctness ...
 
If the resistance of a circuit INCREASES then the current in that circuit  
will actually DECREASE.  Current = Voltage divided by Resistance.   (This is the 
famous Ohm's Law)
 
So while the below mentioned circuit breaker may likely be the problem, and  
perhaps it is the connections at the circuit breaker that are building up too  
much resistance,  it would NOT cause too the circuit to draw more  current.  
It actually would be less!
 
However, that being said... the increased resistance of the poor connection  
would cause more power to be lost at the connection, Power = Current²  
(squared) times Resistance.  Since this lost power will turn into  heat, it certainly 
could cause the circuit break to open the circuit.
 
Since the resistance of the connections is just a small fraction of the  
total resistance of the circuit, even if the contact resistance doubled the  
current would not drop much but the power lost (heat developed)  would rise  by 
about 4 times  (doubled ie 2 squared = 4).
 
Any comments on my math?
 
Of course if the blower motor was going bad and ITS resistance was  too LOW 
(ie its windings partly shorting out) then that Would cause too  much current 
to flow in the circuit which could also open the circuit  breaker....
 
Check the connections and make sure you have the upgraded ?40 AMP  breaker.
 
Now back to your regularly scheduled program....
 
Dave Delman
 
D² & 06530 + 2700 ohms



Craig,

I have the same issue with my DeLorean although  my blower motor usually cuts 
out on a hot day in traffic after about 10  minutes.  There is a circuit 
breaker for the blower motor.  I would  guess that perhaps your blower motor is 
pulling too much current.  Have  you checked your connections to make sure they 
are clean so you aren't  building up too much resistance, and thus drawing 
more  current?







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