Well, yeah... Assuming a perfect system (HA!) Engine is 2849cc 4-stroke, meaning it draws half its capacity every revolution So 5000 x 2849 x 0.5 / 1000 = 7122.5 l/min (which according to www.onlineconversion.com) = 251.5 cf/min Now that's at a pressure of 1 bar (atmosphere) and you are talking about 7psi (14.7psi = 1bar) = 0.48bar of boost so that's 1.48 x 251 = 371 cfm at 7psi of boost (and what fantastic swapping of units I must admit!) - I'm not sure I'm right about the flow under boost but it seems to makes sense to me! I'd go bigger because the PRV can safely be revved to 6500rpm if the breathing's good. Martin Nick wrote: >Is there a figure or >a formula to know how much air a Delorean engine will consume at >5000 rpm? > > To address comments privately to the moderating team, please address: moderators@xxxxxxxxxxx For more info on the list, tech articles, cars for sale see www.dmcnews.com To search the archives or view files, log in at http://groups.yahoo.com/group/dmcnews Yahoo! Groups Links <*> To visit your group on the web, go to: http://groups.yahoo.com/group/dmcnews/ <*> To unsubscribe from this group, send an email to: dmcnews-unsubscribe@xxxxxxxxxxxxxxx <*> Your use of Yahoo! Groups is subject to: http://docs.yahoo.com/info/terms/